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5a^2-75a+90=0
a = 5; b = -75; c = +90;
Δ = b2-4ac
Δ = -752-4·5·90
Δ = 3825
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3825}=\sqrt{225*17}=\sqrt{225}*\sqrt{17}=15\sqrt{17}$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-75)-15\sqrt{17}}{2*5}=\frac{75-15\sqrt{17}}{10} $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-75)+15\sqrt{17}}{2*5}=\frac{75+15\sqrt{17}}{10} $
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